What is the answer to solvefor m,(m+2)x^2-2mx+4=0 ?

The answer to solvefor m,(m+2)x^2-2mx+4=0 is m=(-4-2x^2)/(x(-2+x));\quad x\ne 0,x\ne 2

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solvefor m,(m+2)x^2-2mx+4=0

solve for

m, (m + 2) x^{2} - 2 m x + 4 = 0

m = \frac{- 4 - 2 x ^{2}}{x ( - 2 + x )}; x \neq = 0, x \neq = 2

Solution steps

(m + 2) x^{2} - 2 m x + 4 = 0

Move

4

to the right side

(m + 2) x^{2} - 2 m x = - 4

Expand

(m + 2) x^{2} - 2 m x : m x^{2} + 2 x^{2} - 2 m x

m x^{2} + 2 x^{2} - 2 m x = - 4

Move

2 x^{2}

to the right side

m x^{2} - 2 m x = - 4 - 2 x^{2}

Factor

m x^{2} - 2 m x : m x (x - 2)

m x (x - 2) = - 4 - 2 x^{2}

Divide both sides by

x (x - 2); x \neq = 0, x \neq = 2

m = \frac{- 4 - 2 x ^{2}}{x ( - 2 + x )}; x \neq = 0, x \neq = 2

x, 5 x + 3 y + 6 z = 30

\frac{x + 12}{2} = 10

3 p - 16 = 4 (p - 5) + p + 4

k, \frac{1 + ai}{a + i} + \frac{a + 3 i}{1 - ai} = ki

4 x - 7 = 3 - x

What is the answer to solvefor m,(m+2)x^2-2mx+4=0 ?
The answer to solvefor m,(m+2)x^2-2mx+4=0 is m=(-4-2x^2)/(x(-2+x));\quad x\ne 0,x\ne 2