What is the answer to solvefor y,z=3x^3+3x^2y ?

The answer to solvefor y,z=3x^3+3x^2y is y=(z-3x^3)/(3x^2);\quad x\ne 0

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solvefor y,z=3x^3+3x^2y

solve for

y, z = 3 x^{3} + 3 x^{2} y

y = \frac{z - 3 x ^{3}}{3 x ^{2}}; x \neq = 0

Solution steps

z = 3 x^{3} + 3 x^{2} y

Switch sides

3 x^{3} + 3 x^{2} y = z

Move

3 x^{3}

to the right side

3 x^{2} y = z - 3 x^{3}

Divide both sides by

3 x^{2}; x \neq = 0

y = \frac{z - 3 x ^{3}}{3 x ^{2}}; x \neq = 0

M = - 16 + - 25

3 (2 x + 5) = 4 x

3 x + 12 = 3

3 x + 1 = 28

x, p x + q x = a

What is the answer to solvefor y,z=3x^3+3x^2y ?
The answer to solvefor y,z=3x^3+3x^2y is y=(z-3x^3)/(3x^2);\quad x\ne 0