What is the answer to (3x-1}{15}+\frac{x-4)/5-(x+4)/3 =-2 ?

The answer to (3x-1}{15}+\frac{x-4)/5-(x+4)/3 =-2 is x=3

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(3x-1}{15}+\frac{x-4)/5-(x+4)/3 =-2

\frac{3 x - 1}{15} + \frac{x - 4}{5} - \frac{x + 4}{3} = - 2

x = 3

Solution steps

\frac{3 x - 1}{15} + \frac{x - 4}{5} - \frac{x + 4}{3} = - 2

Multiply by LCM

3 x - 1 + 3 (x - 4) - 5 (x + 4) = - 30

Expand

3 x - 1 + 3 (x - 4) - 5 (x + 4) : x - 33

x - 33 = - 30

Move

33

to the right side

x = 3

4 x - 0.2 = 1.9

x, - 2 x + 2 y = 5

- 2.4 + \frac{a}{0.5} = - 7

11 c + 78 = 5 c + 48

2 \cdot + y = 1

What is the answer to (3x-1}{15}+\frac{x-4)/5-(x+4)/3 =-2 ?
The answer to (3x-1}{15}+\frac{x-4)/5-(x+4)/3 =-2 is x=3
Solve for x: (3x-1}{15}+\frac{x-4)/5-(x+4)/3 =-2
The solution is x=3