What is the answer to solvefor z,z+3a+5b+4c+z=3a+5b+5c ?

The answer to solvefor z,z+3a+5b+4c+z=3a+5b+5c is z= c/2

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solvefor z,z+3a+5b+4c+z=3a+5b+5c

solve for

z, z + 3 a + 5 b + 4 c + z = 3 a + 5 b + 5 c

z = \frac{c}{2}

Solution steps

z + 3 a + 5 b + 4 c + z = 3 a + 5 b + 5 c

Subtract

3 a + 5 b

from both sides

z + 3 a + 5 b + 4 c + z - (3 a + 5 b) = 3 a + 5 b + 5 c - (3 a + 5 b)

Simplify

z + 4 c + z = 5 c

Group like terms

z + z + 4 c = 5 c

Add similar elements:

z + z = 2 z

2 z + 4 c = 5 c

Move

4 c

to the right side

2 z = c

Divide both sides by

2

z = \frac{c}{2}

4 x + 3 = 2 x - 7

\frac{k - 4}{3} = 2

x - 5 = 4 (x + 3) - 2 (x + 5)

4 x - 7 = 2 x - 8

3 x - 5 = x - 2

What is the answer to solvefor z,z+3a+5b+4c+z=3a+5b+5c ?
The answer to solvefor z,z+3a+5b+4c+z=3a+5b+5c is z= c/2