What is the answer to solvefor x,(b-2)x-3y+a=0 ?

The answer to solvefor x,(b-2)x-3y+a=0 is x=(3y-a)/(b-2);\quad b\ne 2

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solvefor x,(b-2)x-3y+a=0

solve for

x, (b - 2) x - 3 y + a = 0

x = \frac{3 y - a}{b - 2}; b \neq = 2

Solution steps

(b - 2) x - 3 y + a = 0

Move

3 y

to the right side

(b - 2) x + a = 3 y

Move

a

to the right side

(b - 2) x = 3 y - a

Divide both sides by

b - 2; b \neq = 2

x = \frac{3 y - a}{b - 2}; b \neq = 2

3 x = \frac{x}{3} + \frac{4}{3}

4 - 2 x + 13 = 10 - 9 x + 7

a, 0 = a e^{0} + b e^{- 0}

5 x + [- 2 x + (- x + 6)] = 18 - [- (7 x + 6) - (3 x - 24)]

- 2 - 2 x = 0

What is the answer to solvefor x,(b-2)x-3y+a=0 ?
The answer to solvefor x,(b-2)x-3y+a=0 is x=(3y-a)/(b-2);\quad b\ne 2