What are the solutions to the equation 4-x^2=-16 ?

The solutions to the equation 4-x^2=-16 are x=2sqrt(5),x=-2sqrt(5)

Find the zeros of 4-x^2=-16

The zeros of 4-x^2=-16 are x=2sqrt(5),x=-2sqrt(5)

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4 - x^{2} = - 16

x = 25, x = - 25

Decimal Notation

x = 4.47213 \dots, x = - 4.47213 \dots

Solution steps

4 - x^{2} = - 16

Move

4

to the right side

- x^{2} = - 20

Divide both sides by

- 1

x^{2} = 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 20, x = - 20

20 = 25

- 20 = - 25

x = 25, x = - 25

(2 x - 5)^{4} (x - 1)^{3} (x + 1) \leq 0

x^{3} + x^{2} - 9 x - 9

x^{2} - 18 x = 40

m^{2} + 9 m + 20

\frac{x}{1} - 9 < - 10

What are the solutions to the equation 4-x^2=-16 ?
The solutions to the equation 4-x^2=-16 are x=2sqrt(5),x=-2sqrt(5)
Find the zeros of 4-x^2=-16
The zeros of 4-x^2=-16 are x=2sqrt(5),x=-2sqrt(5)