What are the solutions to the equation 4t^2+6t+3=-2t ?

The solutions to the equation 4t^2+6t+3=-2t are t=-1/2 ,t=-3/2

Find the zeros of 4t^2+6t+3=-2t

The zeros of 4t^2+6t+3=-2t are t=-1/2 ,t=-3/2

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4 t^{2} + 6 t + 3 = - 2 t

t = - \frac{1}{2}, t = - \frac{3}{2}

Solution steps

4 t^{2} + 6 t + 3 = - 2 t

Move

2 t

to the left side

4 t^{2} + 8 t + 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 3 = 4

t_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- 8 + 4}{2 \cdot 4}, t_{2} = \frac{- 8 - 4}{2 \cdot 4}

t = \frac{- 8 + 4}{2 \cdot 4} : - \frac{1}{2}

t = \frac{- 8 - 4}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

t = - \frac{1}{2}, t = - \frac{3}{2}

6 - 6 (3 - 2 x) < 5 (1 - x)

10 x + 1 > 8 x + 5

(2 x + 3)^{2} - (x - 4)^{2}

0.0 4^{2}

\frac{5 ^{23}}{5 ^{21}}

What are the solutions to the equation 4t^2+6t+3=-2t ?
The solutions to the equation 4t^2+6t+3=-2t are t=-1/2 ,t=-3/2
Find the zeros of 4t^2+6t+3=-2t
The zeros of 4t^2+6t+3=-2t are t=-1/2 ,t=-3/2