What is the answer to (3x-10)+(6x-1)+(4x-3)+(2x-1)=360 ?

The answer to (3x-10)+(6x-1)+(4x-3)+(2x-1)=360 is x=25

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(3x-10)+(6x-1)+(4x-3)+(2x-1)=360

(3 x - 10) + (6 x - 1) + (4 x - 3) + (2 x - 1) = 360

x = 25

Solution steps

(3 x - 10) + (6 x - 1) + (4 x - 3) + (2 x - 1) = 360

Remove parentheses:

(a) = a

3 x - 10 + 6 x - 1 + 4 x - 3 + 2 x - 1 = 360

Group like terms

3 x + 6 x + 4 x + 2 x - 10 - 1 - 3 - 1 = 360

Add similar elements:

3 x + 6 x + 4 x + 2 x = 15 x

15 x - 10 - 1 - 3 - 1 = 360

Subtract the numbers:

- 10 - 1 - 3 - 1 = - 15

15 x - 15 = 360

Move

15

to the right side

15 x = 375

Divide both sides by

15

x = 25

\frac{X - 1}{6} - \frac{X - 3}{2} = - 1

a, a + b - c - 3 d + 2 e = f + 2

x, 4 cos (x) sin (y) = 1

\frac{x + 4}{3} = \frac{x - 2}{3}

3 (1 - (1 - 2 (1 - x))) = - 2 (x - 2)

What is the answer to (3x-10)+(6x-1)+(4x-3)+(2x-1)=360 ?
The answer to (3x-10)+(6x-1)+(4x-3)+(2x-1)=360 is x=25
Solve for x: (3x-10)+(6x-1)+(4x-3)+(2x-1)=360
The solution is x=25