What is the answer to solvefor x,6xy=3y^2+x+y ?

The answer to solvefor x,6xy=3y^2+x+y is x=(3y^2+y)/(6y-1);\quad y\ne 1/6

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solvefor x,6xy=3y^2+x+y

solve for

x, 6 x y = 3 y^{2} + x + y

x = \frac{3 y ^{2} + y}{6 y - 1}; y \neq = \frac{1}{6}

Solution steps

6 x y = 3 y^{2} + x + y

Move

x

to the left side

6 x y - x = 3 y^{2} + y

Factor

6 x y - x : x (6 y - 1)

x (6 y - 1) = 3 y^{2} + y

Divide both sides by

6 y - 1; y \neq = \frac{1}{6}

x = \frac{3 y ^{2} + y}{6 y - 1}; y \neq = \frac{1}{6}

3 (x - 1) + 5 = 3 (1 + 5 x)

2 (4 p - 3) = 2 (3 p - 5)

10 - 2 (3 x - 4) = (2 x + 2)

C = \frac{4 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4}}{4 - \frac{1}{2} - \frac{1}{3} - \frac{1}{4}}

\frac{w}{4} + \frac{11}{12} = \frac{1}{2} - \frac{w}{6}

What is the answer to solvefor x,6xy=3y^2+x+y ?
The answer to solvefor x,6xy=3y^2+x+y is x=(3y^2+y)/(6y-1);\quad y\ne 1/6