What are the solutions to the equation v^2=-16 ?

The solutions to the equation v^2=-16 are v=4i,v=-4i

Find the zeros of v^2=-16

The zeros of v^2=-16 are v=4i,v=-4i

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v^{2} = - 16

v = 4 i, v = - 4 i

Solution steps

v^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = - 16, v = - - 16

- 16 = 4 i

- - 16 = - 4 i

v = 4 i, v = - 4 i

\frac{4}{3} - \frac{1}{2} x \geq \frac{1}{6} + x

x^{2} - 6 x - 49 = 6 x

2 x + 1 = - 9

∣ 2 x - 5 ∣ \leq ∣ 5 x + 4 ∣

- (x + 3) + 0.7 \leq 0.1 (x + \frac{1}{2})

What are the solutions to the equation v^2=-16 ?
The solutions to the equation v^2=-16 are v=4i,v=-4i
Find the zeros of v^2=-16
The zeros of v^2=-16 are v=4i,v=-4i