What is the answer to log_{10}(3)(2x+3)=5 ?

The answer to log_{10}(3)(2x+3)=5 is x=(5-3log_{10}(3))/(2log_{10)(3)}

Solve for x: log_{10}(3)(2x+3)=5

The solution is x=(5-3log_{10}(3))/(2log_{10)(3)}

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lo g_{10} (3) (2 x + 3) = 5

x = \frac{5 - 3 lo g _{10} ( 3 )}{2 lo g _{10} ( 3 )}

Decimal Notation

x = 3.73975 \dots

Solution steps

lo g_{10} (3) (2 x + 3) = 5

Divide both sides by

lo g_{10} (3)

2 x + 3 = \frac{5}{lo g _{10} ( 3 )}

Move

3

to the right side

2 x = \frac{5}{lo g _{10} ( 3 )} - 3

Divide both sides by

2

x = \frac{5 - 3 lo g _{10} ( 3 )}{2 lo g _{10} ( 3 )}

- 4 x - 5 = - 3 (2 x + 6) - 3

3 (n + 4) - 20 = 13 n - 4

2 (x - 5) = 3 - (4 + x)

\frac{2 - x}{3} - \frac{3 - 2 x}{2} = \frac{1 + x}{2}

- 15 = x + 10

What is the answer to log_{10}(3)(2x+3)=5 ?
The answer to log_{10}(3)(2x+3)=5 is x=(5-3log_{10}(3))/(2log_{10)(3)}
Solve for x: log_{10}(3)(2x+3)=5
The solution is x=(5-3log_{10}(3))/(2log_{10)(3)}