What is the answer to solvefor x,y=f(x-2)-3 ?

The answer to solvefor x,y=f(x-2)-3 is x=(y+3)/f+2;\quad f\ne 0

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solvefor x,y=f(x-2)-3

solve for

x, y = f (x - 2) - 3

x = \frac{y + 3}{f} + 2; f \neq = 0

Solution steps

y = f (x - 2) - 3

Switch sides

f (x - 2) - 3 = y

Move

3

to the right side

f (x - 2) = y + 3

Divide both sides by

f; f \neq = 0

x - 2 = \frac{y + 3}{f}; f \neq = 0

Move

2

to the right side

x = \frac{y + 3}{f} + 2; f \neq = 0

x, 5 x + 6 y = 10

x (- 6 - 8 i) = \frac{1}{2} - \frac{3}{4} i

- 3 x + \frac{5 x}{9} = \frac{2}{3} - 2 x

\frac{5 X}{4} - \frac{3}{17} (X - 20) - (2 X - 1) = \frac{X + 24}{34}

26 - 2 x = 12

What is the answer to solvefor x,y=f(x-2)-3 ?
The answer to solvefor x,y=f(x-2)-3 is x=(y+3)/f+2;\quad f\ne 0