What are the solutions to the equation -2x^2+2=0 ?

The solutions to the equation -2x^2+2=0 are x=1,x=-1

Find the zeros of -2x^2+2=0

The zeros of -2x^2+2=0 are x=1,x=-1

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- 2 x^{2} + 2 = 0

x = 1, x = - 1

Solution steps

- 2 x^{2} + 2 = 0

Move

2

to the right side

- 2 x^{2} = - 2

Divide both sides by

- 2

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

(11 a - 4) (2 a - 4) = 0

9 (8 - x) = - 36

\frac{x}{8} = - 6

5 m^{2} - 500 = 625

∣ 4 x - 3 ∣ + 3 = 5

What are the solutions to the equation -2x^2+2=0 ?
The solutions to the equation -2x^2+2=0 are x=1,x=-1
Find the zeros of -2x^2+2=0
The zeros of -2x^2+2=0 are x=1,x=-1