What is the answer to solvefor x,2xy^2-2x+6=0 ?

The answer to solvefor x,2xy^2-2x+6=0 is x=-3/(y^2-1);\quad y\ne 1,y\ne-1

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solvefor x,2xy^2-2x+6=0

solve for

x, 2 x y^{2} - 2 x + 6 = 0

x = - \frac{3}{y ^{2} - 1}; y \neq = 1, y \neq = - 1

Solution steps

2 x y^{2} - 2 x + 6 = 0

Move

6

to the right side

2 x y^{2} - 2 x = - 6

Factor

2 x y^{2} - 2 x : 2 x (y^{2} - 1)

2 x (y^{2} - 1) = - 6

Divide both sides by

2 (y^{2} - 1); y \neq = 1, y \neq = - 1

x = - \frac{3}{y ^{2} - 1}; y \neq = 1, y \neq = - 1

8 x - 7 = 6 x + 7

4 - 2 x = 8

- 9.81 = \frac{0 - V}{1.25}

- 2 (4 + 3 x) = 3 (x - 2)

3 (x + 1) = 3

What is the answer to solvefor x,2xy^2-2x+6=0 ?
The answer to solvefor x,2xy^2-2x+6=0 is x=-3/(y^2-1);\quad y\ne 1,y\ne-1