What is the answer to 3m-(2-m)=-2(2-3m)+3m^0 ?

The answer to 3m-(2-m)=-2(2-3m)+3m^0 is m=-1/2

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3m-(2-m)=-2(2-3m)+3m^0

3 m - (2 - m) = - 2 (2 - 3 m) + 3 m^{0}

m = - \frac{1}{2}

Decimal Notation

m = - 0.5

Solution steps

3 m - (2 - m) = - 2 (2 - 3 m) + 3 m^{0}

Apply rule

a^{0} = 1, a \neq = 0

m^{0} = 1

3 m - (2 - m) = - 2 (- 3 m + 2) + 3 \cdot 1

Multiply the numbers:

3 \cdot 1 = 3

3 m - (2 - m) = - 2 (2 - 3 m) + 3

Expand

3 m - (2 - m) : 4 m - 2

Expand

- 2 (2 - 3 m) + 3 : 6 m - 1

4 m - 2 = 6 m - 1

Move

2

to the right side

4 m = 6 m + 1

Move

6 m

to the left side

- 2 m = 1

Divide both sides by

- 2

m = - \frac{1}{2}

X, - 7 X - 9 Y = - 59

20 x + 4 (x - 9) = 35 x - 10

- 3 x + 14 - x = 5 x - 6 - 4 x

y, y + 7 = \frac{7}{5} (x + 3)

h (4) = - 4 (4) + 2

What is the answer to 3m-(2-m)=-2(2-3m)+3m^0 ?
The answer to 3m-(2-m)=-2(2-3m)+3m^0 is m=-1/2
Solve for m: 3m-(2-m)=-2(2-3m)+3m^0
The solution is m=-1/2