What is the answer to solvefor y,x^{-4}y=xe^x-e^x+c ?

The answer to solvefor y,x^{-4}y=xe^x-e^x+c is y=e^xx^5-e^xx^4+x^4c;\quad x\ne 0

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solvefor y,x^{-4}y=xe^x-e^x+c

solve for

y, x^{- 4} y = x e^{x} - e^{x} + c

y = e^{x} x^{5} - e^{x} x^{4} + x^{4} c; x \neq = 0

Solution steps

x^{- 4} y = x e^{x} - e^{x} + c

Simplify

x^{- 4} : \frac{1}{x ^{4}}

\frac{1}{x ^{4}} y = x e^{x} - e^{x} + c

Multiply both sides by

x^{4}

y = e^{x} x^{5} - e^{x} x^{4} + x^{4} c; x \neq = 0

4 a + 3 a - 8 = 2 a + a + 4

y, y + 1 = x

6 y = 30

100 - 10 x = 0

2 (x + 6) = 4

What is the answer to solvefor y,x^{-4}y=xe^x-e^x+c ?
The answer to solvefor y,x^{-4}y=xe^x-e^x+c is y=e^xx^5-e^xx^4+x^4c;\quad x\ne 0