What is the answer to solvefor x,y[n]=x[n]+x[n+2] ?

The answer to solvefor x,y[n]=x[n]+x[n+2] is x=(ny)/(2(n+1));\quad n\ne-1

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solvefor x,y[n]=x[n]+x[n+2]

solve for

x, y [n] = x [n] + x [n + 2]

x = \frac{n y}{2 ( n + 1 )}; n \neq = - 1

Solution steps

y [n] = x [n] + x [n + 2]

Switch sides

x [n] + x [n + 2] = y [n]

n x + x (n + 2) = n y

Expand

x (n + 2) : n x + 2 x

n x + n x + 2 x = n y

Add similar elements:

n x + n x = 2 n x

2 n x + 2 x = n y

Factor

2 n x + 2 x : 2 x (n + 1)

2 x (n + 1) = n y

Divide both sides by

2 (n + 1); n \neq = - 1

x = \frac{n y}{2 ( n + 1 )}; n \neq = - 1

7 x - 9 = 33

x, x y + y^{2} = 25

x, 5 x + 4 y = 40

3 x - 5 + 2 x = 7 x + 2

E = \frac{2 \frac{1}{2} + 3 \frac{1}{3}}{4 \frac{1}{4} + 6 \frac{1}{6}}

What is the answer to solvefor x,y[n]=x[n]+x[n+2] ?
The answer to solvefor x,y[n]=x[n]+x[n+2] is x=(ny)/(2(n+1));\quad n\ne-1