What is the answer to (2x+1)/4-(3(3-x))/2 =(56+x)/(16) ?

The answer to (2x+1)/4-(3(3-x))/2 =(56+x)/(16) is x=4

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(2x+1)/4-(3(3-x))/2 =(56+x)/(16)

\frac{2 x + 1}{4} - \frac{3 ( 3 - x )}{2} = \frac{56 + x}{16}

x = 4

Solution steps

\frac{2 x + 1}{4} - \frac{3 ( 3 - x )}{2} = \frac{56 + x}{16}

Multiply by LCM

4 (2 x + 1) - 24 (- x + 3) = 56 + x

Expand

4 (2 x + 1) - 24 (- x + 3) : 32 x - 68

32 x - 68 = 56 + x

Move

68

to the right side

32 x = x + 124

Move

x

to the left side

31 x = 124

Divide both sides by

31

x = 4

\frac{3}{4} x - \frac{5}{2} = \frac{5}{2} x - \frac{11}{4}

x, y + x = 4

x, \frac{x}{5} + \frac{y}{3} = 9

- 2 (x - 1) = 2 (x + 1) - 4

\frac{7}{2} \cdot (\frac{4}{5} x + \frac{3}{7}) + 2 = \frac{5}{2} - \frac{2}{5}

What is the answer to (2x+1)/4-(3(3-x))/2 =(56+x)/(16) ?
The answer to (2x+1)/4-(3(3-x))/2 =(56+x)/(16) is x=4
Solve for x: (2x+1)/4-(3(3-x))/2 =(56+x)/(16)
The solution is x=4