What is the answer to solvefor x,mx-ny=m^2+n^2 ?

The answer to solvefor x,mx-ny=m^2+n^2 is x=(m^2+n^2+ny)/m ;\quad m\ne 0

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solvefor x,mx-ny=m^2+n^2

solve for

x, m x - n y = m^{2} + n^{2}

x = \frac{m ^{2} + n ^{2} + n y}{m}; m \neq = 0

Solution steps

m x - n y = m^{2} + n^{2}

Move

n y

to the right side

m x = m^{2} + n^{2} + n y

Divide both sides by

m; m \neq = 0

x = \frac{m ^{2} + n ^{2} + n y}{m}; m \neq = 0

5 x - (2 x + 4) = (3 x + 1) - (2 x - 3)

x, \frac{1}{4} y = 14 x

2 x + 1 = 21

4 x + 1 = 5 x - 8

\frac{5 t}{6} - 2 \frac{1}{2} = \frac{3}{4}

What is the answer to solvefor x,mx-ny=m^2+n^2 ?
The answer to solvefor x,mx-ny=m^2+n^2 is x=(m^2+n^2+ny)/m ;\quad m\ne 0