What is the answer to solvefor u,h(n)=u(n-2)-u(n-12) ?

The answer to solvefor u,h(n)=u(n-2)-u(n-12) is u=(nh)/(10)

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solvefor u,h(n)=u(n-2)-u(n-12)

solve for

u, h (n) = u (n - 2) - u (n - 12)

u = \frac{nh}{10}

Solution steps

h (n) = u (n - 2) - u (n - 12)

Switch sides

u (n - 2) - u (n - 12) = hn

u (n - 2) - u (n - 12) = nh

Expand

u (n - 2) - u (n - 12) : 10 u

10 u = nh

Divide both sides by

10

u = \frac{nh}{10}

7 (2 a + 1) = 35

x, p x - 18 = 4

4 (x - 2) = 12 x - 10 - 8 x + 6

t, a = p (1 + r t)

13 (\frac{5 z + 23}{9}) - 6 z = 32

What is the answer to solvefor u,h(n)=u(n-2)-u(n-12) ?
The answer to solvefor u,h(n)=u(n-2)-u(n-12) is u=(nh)/(10)