What are the solutions to the equation 2x^2+6x-9=0 ?

The solutions to the equation 2x^2+6x-9=0 are x=(3(sqrt(3)-1))/2 ,x=-(3(1+sqrt(3)))/2

Find the zeros of 2x^2+6x-9=0

The zeros of 2x^2+6x-9=0 are x=(3(sqrt(3)-1))/2 ,x=-(3(1+sqrt(3)))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 6 x - 9 = 0

x = \frac{3 ( 3 - 1 )}{2}, x = - \frac{3 ( 1 + 3 )}{2}

Decimal Notation

x = 1.09807 \dots, x = - 4.09807 \dots

Solution steps

2 x^{2} + 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 9) = 63

x_{1, 2} = \frac{- 6 \pm 6 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 6 3}{2 \cdot 2}, x_{2} = \frac{- 6 - 6 3}{2 \cdot 2}

x = \frac{- 6 + 6 3}{2 \cdot 2} : \frac{3 ( 3 - 1 )}{2}

x = \frac{- 6 - 6 3}{2 \cdot 2} : - \frac{3 ( 1 + 3 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 3 - 1 )}{2}, x = - \frac{3 ( 1 + 3 )}{2}

x^{2} + (x + 105)^{2} = 19 5^{2}

x + \frac{x}{3} = 4

- 5 (x - 10) = - 35

- 3 + 5 + 6 g = 11 - 3 g

2 x^{2} + 2 x - 12

What are the solutions to the equation 2x^2+6x-9=0 ?
The solutions to the equation 2x^2+6x-9=0 are x=(3(sqrt(3)-1))/2 ,x=-(3(1+sqrt(3)))/2
Find the zeros of 2x^2+6x-9=0
The zeros of 2x^2+6x-9=0 are x=(3(sqrt(3)-1))/2 ,x=-(3(1+sqrt(3)))/2