What is the answer to (4x+2)(4x-6)+2=16(x-2)^2-26 ?

The answer to (4x+2)(4x-6)+2=16(x-2)^2-26 is x=1

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(4x+2)(4x-6)+2=16(x-2)^2-26

(4 x + 2) (4 x - 6) + 2 = 16 (x - 2)^{2} - 26

x = 1

Solution steps

(4 x + 2) (4 x - 6) + 2 = 16 (x - 2)^{2} - 26

Expand

(4 x + 2) (4 x - 6) + 2 : 16 x^{2} - 16 x - 10

Expand

16 (x - 2)^{2} - 26 : 16 x^{2} - 64 x + 38

16 x^{2} - 16 x - 10 = 16 x^{2} - 64 x + 38

Move

10

to the right side

16 x^{2} - 16 x = 16 x^{2} - 64 x + 48

Subtract

16 x^{2} - 64 x

from both sides

16 x^{2} - 16 x - (16 x^{2} - 64 x) = 16 x^{2} - 64 x + 48 - (16 x^{2} - 64 x)

Simplify

48 x = 48

Divide both sides by

48

x = 1

\frac{29}{18} + \frac{1}{2} x = - \frac{5}{3} (x + \frac{1}{3})

4 x - 3 + 2 x + 23 - x = 11 + 6 x + 19

x, 8 x + 10 y = - 30

x, y - 4 = - 2 (x - 6)

3 + 5 x = 5 (x + 2) - 7

What is the answer to (4x+2)(4x-6)+2=16(x-2)^2-26 ?
The answer to (4x+2)(4x-6)+2=16(x-2)^2-26 is x=1
Solve for x: (4x+2)(4x-6)+2=16(x-2)^2-26
The solution is x=1