What are the solutions to the equation 5x^2-12x+4=0 ?

The solutions to the equation 5x^2-12x+4=0 are x=2,x= 2/5

Find the zeros of 5x^2-12x+4=0

The zeros of 5x^2-12x+4=0 are x=2,x= 2/5

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5 x^{2} - 12 x + 4 = 0

x = 2, x = \frac{2}{5}

Decimal Notation

x = 2, x = 0.4

Solution steps

5 x^{2} - 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 \cdot 4 = 8

x_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 5}, x_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 5}

x = \frac{- ( - 12 ) + 8}{2 \cdot 5} : 2

x = \frac{- ( - 12 ) - 8}{2 \cdot 5} : \frac{2}{5}

The solutions to the quadratic equation are:

x = 2, x = \frac{2}{5}

3 x - 4 > 5 or 1 - 2 x \geq 7

6 x^{2} - 6 x - 2 = 0

- 8 x + 1 < 17

\frac{1}{2} \cdot 40

r^{2} - 3 r - 7 = 0

What are the solutions to the equation 5x^2-12x+4=0 ?
The solutions to the equation 5x^2-12x+4=0 are x=2,x= 2/5
Find the zeros of 5x^2-12x+4=0
The zeros of 5x^2-12x+4=0 are x=2,x= 2/5