What is the answer to f(sqrt(3))=(sqrt(3))^2-3(sqrt(3))+4 ?

The answer to f(sqrt(3))=(sqrt(3))^2-3(sqrt(3))+4 is f=(7-3sqrt(3))/(sqrt(3))

Solve for f: f(sqrt(3))=(sqrt(3))^2-3(sqrt(3))+4

The solution is f=(7-3sqrt(3))/(sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f (3) = (3)^{2} - 3 (3) + 4

f = \frac{7 - 3 3}{3}

Decimal Notation

f = 1.04145 \dots

Solution steps

f (3) = (3)^{2} - 3 (3) + 4

Simplify

(3)^{2} - 3 (3) + 4 : 7 - 33

f (3) = 7 - 33

Divide both sides by

3

f = \frac{7 - 3 3}{3}

x, y + 6 = - \frac{1}{3} (x - 15)

r + 3 = 3 (r - 5)

\frac{2 x}{5} + 5 = 7

x - 9 = 37

3 (x - 1) - 2 (7) = 1

What is the answer to f(sqrt(3))=(sqrt(3))^2-3(sqrt(3))+4 ?
The answer to f(sqrt(3))=(sqrt(3))^2-3(sqrt(3))+4 is f=(7-3sqrt(3))/(sqrt(3))
Solve for f: f(sqrt(3))=(sqrt(3))^2-3(sqrt(3))+4
The solution is f=(7-3sqrt(3))/(sqrt(3))