What is the answer to ((3x-1)^2)/3 =(3x+1)(x+2) ?

The answer to ((3x-1)^2)/3 =(3x+1)(x+2) is x=-5/27

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((3x-1)^2)/3 =(3x+1)(x+2)

\frac{( 3 x - 1 ) ^{2}}{3} = (3 x + 1) (x + 2)

x = - \frac{5}{27}

Decimal Notation

x = - 0.18518 \dots

Solution steps

\frac{( 3 x - 1 ) ^{2}}{3} = (3 x + 1) (x + 2)

Multiply both sides by

3

(3 x - 1)^{2} = 3 (3 x + 1) (x + 2)

Expand

(3 x + 1) (x + 2) : 3 x^{2} + 7 x + 2

9 x^{2} - 6 x + 1 = 3 (3 x^{2} + 7 x + 2)

Expand

3 (3 x^{2} + 7 x + 2) : 9 x^{2} + 21 x + 6

9 x^{2} - 6 x + 1 = 9 x^{2} + 21 x + 6

Expand

(3 x - 1)^{2} : 9 x^{2} - 6 x + 1

9 x^{2} - 6 x + 1 = 9 x^{2} + 21 x + 6

Move

1

to the right side

9 x^{2} - 6 x = 9 x^{2} + 21 x + 5

Subtract

9 x^{2} + 21 x

from both sides

9 x^{2} - 6 x - (9 x^{2} + 21 x) = 9 x^{2} + 21 x + 5 - (9 x^{2} + 21 x)

Simplify

- 27 x = 5

Divide both sides by

- 27

x = - \frac{5}{27}

\frac{3 x}{2} - 12 = 5

4 x - 4 = 12

x, x + 2 y - z = 4

C = \frac{50000}{( 1 + 0.04 ) ^{3.6666600000000 \dots}}

\frac{2 x + 1}{3} - \frac{x - 1}{2} = \frac{5}{6}

What is the answer to ((3x-1)^2)/3 =(3x+1)(x+2) ?
The answer to ((3x-1)^2)/3 =(3x+1)(x+2) is x=-5/27
Solve for x: ((3x-1)^2)/3 =(3x+1)(x+2)
The solution is x=-5/27