What is the answer to 3[(x-1)/3-2x]=(x/3+1/2)4+3/2 (2-2x) ?

The answer to 3[(x-1)/3-2x]=(x/3+1/2)4+3/2 (2-2x) is x=-9/5

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3[(x-1)/3-2x]=(x/3+1/2)4+3/2 (2-2x)

3 [\frac{x - 1}{3} - 2 x] = (\frac{x}{3} + \frac{1}{2}) 4 + \frac{3}{2} (2 - 2 x)

x = - \frac{9}{5}

Decimal Notation

x = - 1.8

Solution steps

3 [\frac{x - 1}{3} - 2 x] = (\frac{x}{3} + \frac{1}{2}) \cdot 4 + \frac{3}{2} (2 - 2 x)

Multiply

\frac{3}{2} (2 - 2 x) : \frac{3 ( - 2 x + 2 )}{2}

3 [\frac{x - 1}{3} - 2 x] = 4 (\frac{x}{3} + \frac{1}{2}) + \frac{3 ( 2 - 2 x )}{2}

Expand

3 (\frac{x - 1}{3} - 2 x) : - 5 x - 1

Expand

4 (\frac{x}{3} + \frac{1}{2}) + \frac{3 ( 2 - 2 x )}{2} : - \frac{5 x}{3} + 5

- 5 x - 1 = - \frac{5 x}{3} + 5

Multiply both sides by

3

- 15 x - 3 = - 5 x + 15

Move

3

to the right side

- 15 x = - 5 x + 18

Move

5 x

to the left side

- 10 x = 18

Divide both sides by

- 10

x = - \frac{9}{5}

y, x = 10 y - 12

g, f = s i g

\frac{5 x - 2}{3} = \frac{4 x + 1}{2}

x, x + 8 y = 23

y + \frac{5}{7} = \frac{8}{9}

What is the answer to 3[(x-1)/3-2x]=(x/3+1/2)4+3/2 (2-2x) ?
The answer to 3[(x-1)/3-2x]=(x/3+1/2)4+3/2 (2-2x) is x=-9/5
Solve for x: 3[(x-1)/3-2x]=(x/3+1/2)4+3/2 (2-2x)
The solution is x=-9/5