What is the answer to log_{3}(5^{log_{5}(7)}+2)=x+1 ?

The answer to log_{3}(5^{log_{5}(7)}+2)=x+1 is x=1

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log_{3}(5^{log_{5}(7)}+2)=x+1

lo g_{3} (5^{l o g_{5} (7)} + 2) = x + 1

x = 1

Solution steps

lo g_{3} (5^{l o g_{5} (7)} + 2) = x + 1

Switch sides

x + 1 = lo g_{3} (5^{l o g_{5} (7)} + 2)

Move

1

to the right side

x = 1

y = - 4 (0) + 2

x, 6 y = 2 x

x, e^{z} - x yz = 0

4 (x - 2) + 5 = 3 + 2 (x - 3)

\frac{3}{5} x - \frac{1}{3} x = x - 1

What is the answer to log_{3}(5^{log_{5}(7)}+2)=x+1 ?
The answer to log_{3}(5^{log_{5}(7)}+2)=x+1 is x=1
Solve for x: log_{3}(5^{log_{5}(7)}+2)=x+1
The solution is x=1