What is the answer to solvefor x,y^2(x-2)+2=0 ?

The answer to solvefor x,y^2(x-2)+2=0 is x=-2/(y^2)+2;\quad y\ne 0

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solvefor x,y^2(x-2)+2=0

solve for

x, y^{2} (x - 2) + 2 = 0

x = - \frac{2}{y ^{2}} + 2; y \neq = 0

Solution steps

y^{2} (x - 2) + 2 = 0

Move

2

to the right side

y^{2} (x - 2) = - 2

Divide both sides by

y^{2}; y \neq = 0

x - 2 = - \frac{2}{y ^{2}}; y \neq = 0

Move

2

to the right side

x = - \frac{2}{y ^{2}} + 2; y \neq = 0

2 y - 3 = 2 y - 2

f (u^{1} - u^{2}) = f (u^{1}) - f (u^{2})

\frac{3 x}{4} = \frac{2}{5}

12 x + 6 y = 24, x

x, - 5 x - 4 y = 20

What is the answer to solvefor x,y^2(x-2)+2=0 ?
The answer to solvefor x,y^2(x-2)+2=0 is x=-2/(y^2)+2;\quad y\ne 0