What is factor n^2+n-42 ?

The solution to factor n^2+n-42 is (n-6)(n+7)

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factor n^2+n-42

factor

n^{2} + n - 42

(n - 6) (n + 7)

Solution steps

n^{2} + n - 42

Break the expression into groups

= (n^{2} - 6 n) + (7 n - 42)

Factor out

n

from

n^{2} - 6 n : n (n - 6)

Factor out

7

from

7 n - 42 : 7 (n - 6)

= n (n - 6) + 7 (n - 6)

Factor out common term

n - 6

= (n - 6) (n + 7)

\frac{1}{1 - 2 x} - \frac{1}{1 + 2 x} \leq x

\frac{( \frac{18}{11} )}{( \frac{8}{33} )}

3 x - 5 > 7

\frac{5}{2} + 4

x^{2} + 12 x + 27 \geq 0