What is the answer to solvefor n,\sum k=-2n-3(2k^2-15k+27) ?

The answer to solvefor n,\sum k=-2n-3(2k^2-15k+27) is n=-(\sum k+3(2k^2-15k+27))/2

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solvefor n,\sum k=-2n-3(2k^2-15k+27)

solve for

n, \sum k = - 2 n - 3 (2 k^{2} - 15 k + 27)

n = - \frac{\sum k + 3 ( 2 k ^{2} - 15 k + 27 )}{2}

Solution steps

\sum k = - 2 n - 3 (2 k^{2} - 15 k + 27)

Switch sides

- 2 n - 3 (2 k^{2} - 15 k + 27) = \sum k

Move

3 (2 k^{2} - 15 k + 27)

to the right side

- 2 n = \sum k + 3 (2 k^{2} - 15 k + 27)

Divide both sides by

- 2

n = - \frac{\sum k + 3 ( 2 k ^{2} - 15 k + 27 )}{2}

x, 2 x + 4 y - 5 = 0

6 b + x = 2

2 h + 4 = 0

lo g_{10} (1) = - 3

\frac{x}{2} - \frac{5}{6} = \frac{x}{3} - \frac{x}{5} + 1

What is the answer to solvefor n,\sum k=-2n-3(2k^2-15k+27) ?
The answer to solvefor n,\sum k=-2n-3(2k^2-15k+27) is n=-(\sum k+3(2k^2-15k+27))/2