What is the answer to solvefor x,xy^2-3y^2-4x=8 ?

The answer to solvefor x,xy^2-3y^2-4x=8 is x=(8+3y^2)/(y^2-4);\quad y\ne 2,y\ne-2

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solvefor x,xy^2-3y^2-4x=8

solve for

x, x y^{2} - 3 y^{2} - 4 x = 8

x = \frac{8 + 3 y ^{2}}{y ^{2} - 4}; y \neq = 2, y \neq = - 2

Solution steps

x y^{2} - 3 y^{2} - 4 x = 8

Move

3 y^{2}

to the right side

x y^{2} - 4 x = 8 + 3 y^{2}

Factor

x y^{2} - 4 x : x (y^{2} - 4)

x (y^{2} - 4) = 8 + 3 y^{2}

Divide both sides by

y^{2} - 4; y \neq = 2, y \neq = - 2

x = \frac{8 + 3 y ^{2}}{y ^{2} - 4}; y \neq = 2, y \neq = - 2

x, (\frac{x}{7}) + (\frac{y}{5}) = 1

2 x (2 x + 5) = 4 x^{2} - 3

\frac{75}{0.15} = \frac{0.15 \cdot + x}{0.15}

a, 5 a - 2 b = 3

x, 3 y - 2 x = - 9

What is the answer to solvefor x,xy^2-3y^2-4x=8 ?
The answer to solvefor x,xy^2-3y^2-4x=8 is x=(8+3y^2)/(y^2-4);\quad y\ne 2,y\ne-2