What is the answer to 3(x+4)=9(2x+1)-8(3x+2) ?

The answer to 3(x+4)=9(2x+1)-8(3x+2) is x=-19/9

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3(x+4)=9(2x+1)-8(3x+2)

3 (x + 4) = 9 (2 x + 1) - 8 (3 x + 2)

x = - \frac{19}{9}

Decimal Notation

x = - 2.11111 \dots

Solution steps

3 (x + 4) = 9 (2 x + 1) - 8 (3 x + 2)

Expand

3 (x + 4) : 3 x + 12

Expand

9 (2 x + 1) - 8 (3 x + 2) : - 6 x - 7

3 x + 12 = - 6 x - 7

Move

12

to the right side

3 x = - 6 x - 19

Move

6 x

to the left side

9 x = - 19

Divide both sides by

9

x = - \frac{19}{9}

\frac{x}{10} + \frac{1}{5} = \frac{3}{20}

a, 2 a + 3 b = 12 - 2 (2 b + a)

\frac{\frac{4 + 8 y}{7}}{2} + \frac{y}{3} = 3

38 = - 10 x - 9 + 3 x - 2

x, 8 x + 4 = 6 y + 10

What is the answer to 3(x+4)=9(2x+1)-8(3x+2) ?
The answer to 3(x+4)=9(2x+1)-8(3x+2) is x=-19/9
Solve for x: 3(x+4)=9(2x+1)-8(3x+2)
The solution is x=-19/9