What is the answer to log_{10}(5)(x-1)+log_{10}(5)(x+3)=1 ?

The answer to log_{10}(5)(x-1)+log_{10}(5)(x+3)=1 is x=(1-2log_{10}(5))/(2log_{10)(5)}

Solve for x: log_{10}(5)(x-1)+log_{10}(5)(x+3)=1

The solution is x=(1-2log_{10}(5))/(2log_{10)(5)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} (5) (x - 1) + lo g_{10} (5) (x + 3) = 1

x = \frac{1 - 2 lo g _{10} ( 5 )}{2 lo g _{10} ( 5 )}

Decimal Notation

x = - 0.28466 \dots

Solution steps

lo g_{10} (5) (x - 1) + lo g_{10} (5) (x + 3) = 1

Expand

lo g_{10} (5) (x - 1) + lo g_{10} (5) (x + 3) : 2 lo g_{10} (5) x + 2 lo g_{10} (5)

2 lo g_{10} (5) x + 2 lo g_{10} (5) = 1

Move

2 lo g_{10} (5)

to the right side

2 lo g_{10} (5) x = 1 - 2 lo g_{10} (5)

Divide both sides by

2 lo g_{10} (5)

x = \frac{1 - 2 lo g _{10} ( 5 )}{2 lo g _{10} ( 5 )}

x, y^{2} = 8 p x

\frac{4 x + 1}{3} + 4 = \frac{x + 3}{2} + 2 (x + 2)

\frac{x - 1}{2} - \frac{x - 2}{4} = 2

- 3 x + 3 = - 7 x - 1

10 (2 x - 7) + 3 (x - 2) = 3 (2 - x)

What is the answer to log_{10}(5)(x-1)+log_{10}(5)(x+3)=1 ?
The answer to log_{10}(5)(x-1)+log_{10}(5)(x+3)=1 is x=(1-2log_{10}(5))/(2log_{10)(5)}
Solve for x: log_{10}(5)(x-1)+log_{10}(5)(x+3)=1
The solution is x=(1-2log_{10}(5))/(2log_{10)(5)}