What is the answer to solvefor x,xy+z^3x-2yz=0 ?

The answer to solvefor x,xy+z^3x-2yz=0 is x=(2yz)/(y+z^3);\quad y\ne-z^3

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solvefor x,xy+z^3x-2yz=0

solve for

x, x y + z^{3} x - 2 yz = 0

x = \frac{2 yz}{y + z ^{3}}; y \neq = - z^{3}

Solution steps

x y + z^{3} x - 2 yz = 0

Move

2 yz

to the right side

x y + z^{3} x = 2 yz

Factor

x y + z^{3} x : x (y + z^{3})

x (y + z^{3}) = 2 yz

Divide both sides by

y + z^{3}; y \neq = - z^{3}

x = \frac{2 yz}{y + z ^{3}}; y \neq = - z^{3}

lo g_{10} (6) (x) = 2

- 4 = - 8 - 2 (4 x + 6) - 8 x

- 5 y - 6 y = - 22

h (- 5) = - 4 (- 5) + 2

2 (x + 2) + 3 = 2 (x + 1) + 1

What is the answer to solvefor x,xy+z^3x-2yz=0 ?
The answer to solvefor x,xy+z^3x-2yz=0 is x=(2yz)/(y+z^3);\quad y\ne-z^3