What is the answer to (4x^2-1)/8 =(6x^2+x)/(12) ?

The answer to (4x^2-1)/8 =(6x^2+x)/(12) is x=-3/2

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(4x^2-1)/8 =(6x^2+x)/(12)

\frac{4 x ^{2} - 1}{8} = \frac{6 x ^{2} + x}{12}

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

\frac{4 x ^{2} - 1}{8} = \frac{6 x ^{2} + x}{12}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(4 x^{2} - 1) \cdot 12 = 8 (6 x^{2} + x)

Expand

(4 x^{2} - 1) \cdot 12 : 48 x^{2} - 12

Expand

8 (6 x^{2} + x) : 48 x^{2} + 8 x

48 x^{2} - 12 = 48 x^{2} + 8 x

Move

12

to the right side

48 x^{2} = 48 x^{2} + 8 x + 12

Subtract

48 x^{2} + 8 x

from both sides

48 x^{2} - (48 x^{2} + 8 x) = 48 x^{2} + 8 x + 12 - (48 x^{2} + 8 x)

Simplify

- 8 x = 12

Divide both sides by

- 8

x = - \frac{3}{2}

1240 = \frac{3}{25} x + x

a x + 2 ab = (a + b)^{2} - 2 b^{2} + b x

\frac{2 \cdot 756}{273} = \frac{4 x}{137}

8 - \frac{7 x}{2} = 1

5 + x = 32

What is the answer to (4x^2-1)/8 =(6x^2+x)/(12) ?
The answer to (4x^2-1)/8 =(6x^2+x)/(12) is x=-3/2
Solve for x: (4x^2-1)/8 =(6x^2+x)/(12)
The solution is x=-3/2