What is the answer to (2x+1)/8 =(3x-5)/7 ?

The answer to (2x+1)/8 =(3x-5)/7 is x= 47/10

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(2x+1)/8 =(3x-5)/7

\frac{2 x + 1}{8} = \frac{3 x - 5}{7}

x = \frac{47}{10}

Decimal Notation

x = 4.7

Solution steps

\frac{2 x + 1}{8} = \frac{3 x - 5}{7}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(2 x + 1) \cdot 7 = 8 (3 x - 5)

Expand

(2 x + 1) \cdot 7 : 14 x + 7

Expand

8 (3 x - 5) : 24 x - 40

14 x + 7 = 24 x - 40

Move

7

to the right side

14 x = 24 x - 47

Move

24 x

to the left side

- 10 x = - 47

Divide both sides by

- 10

x = \frac{47}{10}

5 = x - 2

1 + 4 x = 13 + x

\frac{1}{2} (\frac{x}{3} - 1) + \frac{1}{3} (\frac{x}{2} - 2) = \frac{5}{6}

\frac{3 x - 8}{5} = - 4

0.2 = 1200 \cdot 0.12 \cdot 0.06 \cdot x

What is the answer to (2x+1)/8 =(3x-5)/7 ?
The answer to (2x+1)/8 =(3x-5)/7 is x= 47/10
Solve for x: (2x+1)/8 =(3x-5)/7
The solution is x= 47/10