What is the answer to solvefor n,f=2f(n-1)+2 ?

The answer to solvefor n,f=2f(n-1)+2 is n=(f-2)/(2f)+1;\quad f\ne 0

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solvefor n,f=2f(n-1)+2

solve for

n, f = 2 f (n - 1) + 2

n = \frac{f - 2}{2 f} + 1; f \neq = 0

Solution steps

f = 2 f (n - 1) + 2

Switch sides

2 f (n - 1) + 2 = f

Move

2

to the right side

2 f (n - 1) = f - 2

Divide both sides by

2 f; f \neq = 0

n - 1 = \frac{f - 2}{2 f}; f \neq = 0

Move

1

to the right side

n = \frac{f - 2}{2 f} + 1; f \neq = 0

y = - 3 (- 2)^{2}

x, f = lo g_{10} (k) x

\frac{- ( - 10 ) - 60}{( - 5 )} = - 2

F = \frac{1}{2} (0.015) (300)^{2}

0.4624 x + 0.4916 = 9.6655 x - 3.1196

What is the answer to solvefor n,f=2f(n-1)+2 ?
The answer to solvefor n,f=2f(n-1)+2 is n=(f-2)/(2f)+1;\quad f\ne 0