What is the answer to |x^2-4|+x+2=0 ?

The answer to |x^2-4|+x+2=0 is x=-2

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|x^2-4|+x+2=0

x^{2} - 4 + x + 2 = 0

x = - 2

Solution steps

x^{2} - 4 + x + 2 = 0

Find positive and negative intervals

x \leq - 2, - 2 < x < 2, x \geq 2

Solve the inequality for each interval

x = - 2 or No Solution

x = - 2

100 x^{2} - 9

(\frac{x}{3} - \frac{3 y}{2})^{2}

2^{- 1} + 3^{- 1}

\frac{3}{\frac{4}{2}}

- \frac{1}{( 2 + 4 ) ^{2}}