What is the answer to solvefor x,(d^2x)/(dt^2)-tx=2 ?

The answer to solvefor x,(d^2x)/(dt^2)-tx=2 is x=-(2-(d^2x)/(dt^2))/t ;\quad t\ne 0

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solvefor x,(d^2x)/(dt^2)-tx=2

solve for

x, \frac{d ^{2} x}{d t ^{2}} - t x = 2

x = - \frac{2 - \frac{d ^{2} x}{d t ^{2}}}{t}; t \neq = 0

Solution steps

\frac{d ^{2} x}{d t ^{2}} - t x = 2

Move

\frac{d ^{2} x}{d t ^{2}}

to the right side

- t x = 2 - \frac{d ^{2} x}{d t ^{2}}

Divide both sides by

- t; t \neq = 0

x = - \frac{2 - \frac{d ^{2} x}{d t ^{2}}}{t}; t \neq = 0

32 x - 18 = 20 x - 6

3 - 2 x = 4 x + 8

x, - 5 x - 2 y = 0

\frac{x}{0.34} = 4.3

(3 x + 10) + (6 x + 1) + (4 x + 3) + (2 x + 1) = 360

What is the answer to solvefor x,(d^2x)/(dt^2)-tx=2 ?
The answer to solvefor x,(d^2x)/(dt^2)-tx=2 is x=-(2-(d^2x)/(dt^2))/t ;\quad t\ne 0