What is the answer to (2x+3)(x-2)=x+2x^2 ?

The answer to (2x+3)(x-2)=x+2x^2 is x=-3

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(2x+3)(x-2)=x+2x^2

(2 x + 3) (x - 2) = x + 2 x^{2}

x = - 3

Solution steps

(2 x + 3) (x - 2) = x + 2 x^{2}

Expand

(2 x + 3) (x - 2) : 2 x^{2} - x - 6

2 x^{2} - x - 6 = x + 2 x^{2}

Move

6

to the right side

2 x^{2} - x = x + 2 x^{2} + 6

Subtract

x + 2 x^{2}

from both sides

2 x^{2} - x - (x + 2 x^{2}) = x + 2 x^{2} + 6 - (x + 2 x^{2})

Simplify

- 2 x = 6

Divide both sides by

- 2

x = - 3

t, 4 a t - 4 a + 4 b = 4 t - 1

y = \frac{2 ^{2} + 22 e - 1}{( 2 + 10 ) e ^{2}}

2 t - 6 = 0

\frac{x}{6} = \frac{15}{18}

x, 6 x + 5 y - 7 z + 8 t = 9

What is the answer to (2x+3)(x-2)=x+2x^2 ?
The answer to (2x+3)(x-2)=x+2x^2 is x=-3
Solve for x: (2x+3)(x-2)=x+2x^2
The solution is x=-3