What is the answer to 1/3 (2+1/5 (4z-1))= 3/4 z-1/3 ?

The answer to 1/3 (2+1/5 (4z-1))= 3/4 z-1/3 is z= 56/29

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1/3 (2+1/5 (4z-1))= 3/4 z-1/3

\frac{1}{3} (2 + \frac{1}{5} (4 z - 1)) = \frac{3}{4} z - \frac{1}{3}

z = \frac{56}{29}

Decimal Notation

z = 1.93103 \dots

Solution steps

\frac{1}{3} (2 + \frac{1}{5} (4 z - 1)) = \frac{3}{4} z - \frac{1}{3}

Expand

\frac{1}{3} (2 + \frac{1}{5} (4 z - 1)) : \frac{4 z}{15} + \frac{3}{5}

\frac{4 z}{15} + \frac{3}{5} = \frac{3}{4} z - \frac{1}{3}

Move

\frac{3}{5}

to the right side

\frac{4 z}{15} = - \frac{14}{15} + \frac{3}{4} z

Move

\frac{3}{4} z

to the left side

- \frac{29 z}{60} = - \frac{14}{15}

Multiply both sides by

60

- 29 z = - 56

Divide both sides by

- 29

z = \frac{56}{29}

x, y = 2 x - 4

lo g_{5} (2 5^{4}) = 4

x, y - 5 x = 1

4 (x - 3) + 18 = 3 (x + 4)

(4.1 \cdot 0.7 + x \cdot 0.3) = 4

What is the answer to 1/3 (2+1/5 (4z-1))= 3/4 z-1/3 ?
The answer to 1/3 (2+1/5 (4z-1))= 3/4 z-1/3 is z= 56/29
Solve for z: 1/3 (2+1/5 (4z-1))= 3/4 z-1/3
The solution is z= 56/29