What is the answer to 0= x/(2pi)-1/8 (12-x) ?

The answer to 0= x/(2pi)-1/8 (12-x) is x=(12pi)/(4+pi)

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0= x/(2pi)-1/8 (12-x)

0 = \frac{x}{2 π} - \frac{1}{8} (12 - x)

x = \frac{12 π}{4 + π}

Decimal Notation

x = 5.27881 \dots

Solution steps

0 = \frac{x}{2 π} - \frac{1}{8} (12 - x)

Switch sides

\frac{x}{2 π} - \frac{1}{8} (12 - x) = 0

Multiply by LCM

4 x - π (12 - x) = 0

Expand

- π (12 - x) : - 12 π + π x

4 x - 12 π + π x = 0

Move

12 π

to the right side

4 x + π x = 12 π

Factor

4 x + π x : (4 + π) x

(4 + π) x = 12 π

Divide both sides by

4 + π

x = \frac{12 π}{4 + π}

8 x = 96

x, y - 4 x = 0

x, \frac{x y}{2} = 28

x, y - 4 = - 3 (x - 1)

g, g (k) = (7 - k)^{\frac{1}{2}}

What is the answer to 0= x/(2pi)-1/8 (12-x) ?
The answer to 0= x/(2pi)-1/8 (12-x) is x=(12pi)/(4+pi)