What is the answer to solvefor x,x+xy^2-y=0 ?

The answer to solvefor x,x+xy^2-y=0 is x= y/(1+y^2);\quad y\ne i,y\ne-i

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solvefor x,x+xy^2-y=0

solve for

x, x + x y^{2} - y = 0

x = \frac{y}{1 + y ^{2}}; y \neq = i, y \neq = - i

Solution steps

x + x y^{2} - y = 0

Move

y

to the right side

x + x y^{2} = y

Factor

x + x y^{2} : x (1 + y^{2})

x (1 + y^{2}) = y

Divide both sides by

1 + y^{2}; y \neq = i, y \neq = - i

x = \frac{y}{1 + y ^{2}}; y \neq = i, y \neq = - i

X^{2} \cdot X^{3} = X^{2 + 3}

1 x - \frac{4}{3} + \frac{1}{12} = 2

\frac{w - 9}{2} = - 3

13 = 7 + 0.5 \cdot x

\frac{1}{2} z = \frac{2}{5}

What is the answer to solvefor x,x+xy^2-y=0 ?
The answer to solvefor x,x+xy^2-y=0 is x= y/(1+y^2);\quad y\ne i,y\ne-i