What is the answer to (x+3)^2+7=(x+6)(x+4) ?

The answer to (x+3)^2+7=(x+6)(x+4) is x=-2

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(x+3)^2+7=(x+6)(x+4)

(x + 3)^{2} + 7 = (x + 6) (x + 4)

x = - 2

Solution steps

(x + 3)^{2} + 7 = (x + 6) (x + 4)

Expand

(x + 3)^{2} + 7 : x^{2} + 6 x + 16

Expand

(x + 6) (x + 4) : x^{2} + 10 x + 24

x^{2} + 6 x + 16 = x^{2} + 10 x + 24

Move

16

to the right side

x^{2} + 6 x = x^{2} + 10 x + 8

Subtract

x^{2} + 10 x

from both sides

x^{2} + 6 x - (x^{2} + 10 x) = x^{2} + 10 x + 8 - (x^{2} + 10 x)

Simplify

- 4 x = 8

Divide both sides by

- 4

x = - 2

A, A X + BX = C

\frac{3}{5} x + \frac{2}{3} + x = \frac{1}{2} - \frac{1}{5} x

5 x = - 6 x - 33

d, \frac{p ^{2}}{4} + d = 4

(2 x - 1) 0.5 - 4 (x + 2) = 1

What is the answer to (x+3)^2+7=(x+6)(x+4) ?
The answer to (x+3)^2+7=(x+6)(x+4) is x=-2
Solve for x: (x+3)^2+7=(x+6)(x+4)
The solution is x=-2