What are the solutions to the equation x^2-16x+31=0 ?

The solutions to the equation x^2-16x+31=0 are x=8+sqrt(33),x=8-sqrt(33)

Find the zeros of x^2-16x+31=0

The zeros of x^2-16x+31=0 are x=8+sqrt(33),x=8-sqrt(33)

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x^{2} - 16 x + 31 = 0

x = 8 + 33, x = 8 - 33

Decimal Notation

x = 13.74456 \dots, x = 2.25543 \dots

Solution steps

x^{2} - 16 x + 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 31}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 31 = 233

x_{1, 2} = \frac{- ( - 16 ) \pm 2 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 33}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 33}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 33}{2 \cdot 1} : 8 + 33

x = \frac{- ( - 16 ) - 2 33}{2 \cdot 1} : 8 - 33

The solutions to the quadratic equation are:

x = 8 + 33, x = 8 - 33

- 2.5 \leq \frac{1 - 3 y}{2} \leq 1.5

11 a = - 16

5 a^{2} + 60 a + 100

∣ q - 1 ∣ > 4

(4 \cdot 1 0^{10}) (9 \cdot 1 0^{- 5})

What are the solutions to the equation x^2-16x+31=0 ?
The solutions to the equation x^2-16x+31=0 are x=8+sqrt(33),x=8-sqrt(33)
Find the zeros of x^2-16x+31=0
The zeros of x^2-16x+31=0 are x=8+sqrt(33),x=8-sqrt(33)