What is the answer to (x-a}{(a)}+\frac{x-b)/b =2 ?

The answer to (x-a}{(a)}+\frac{x-b)/b =2 is x=(4ab)/(a+b);\quad ab\ne 0,a\ne-b

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(x-a}{(a)}+\frac{x-b)/b =2

\frac{x - a}{( a )} + \frac{x - b}{b} = 2

x = \frac{4 ab}{a + b}; ab \neq = 0, a \neq = - b

Solution steps

\frac{x - a}{( a )} + \frac{x - b}{b} = 2

\frac{x - a}{a} + \frac{x - b}{b} = 2

Multiply by LCM

b (x - a) + a (x - b) = 2 ab; ab \neq = 0

Expand

b (x - a) + a (x - b) : a x + b x - 2 ab

a x + b x - 2 ab = 2 ab; ab \neq = 0

Move

2 ab

to the right side

a x + b x = 4 ab; ab \neq = 0

Factor

a x + b x : x (a + b)

x (a + b) = 4 ab; ab \neq = 0

Divide both sides by

a + b; ab \neq = 0, a \neq = - b

x = \frac{4 ab}{a + b}; ab \neq = 0, a \neq = - b

\frac{1}{3} x + \frac{1}{4} = \frac{2}{5} (x - \frac{3}{4})

1.5 - (9 - 4 x) = 0.5 (8 x + 1)

x, - 6 x - 2 y = 4

x, f = 0

2 (x - 4) + 3 x = 5 x + 7

What is the answer to (x-a}{(a)}+\frac{x-b)/b =2 ?
The answer to (x-a}{(a)}+\frac{x-b)/b =2 is x=(4ab)/(a+b);\quad ab\ne 0,a\ne-b