What is ((-9+12i))/((1+2i)) ?

The solution to ((-9+12i))/((1+2i)) is 3+6i

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simplify ((-9+12i))/((1+2i))

simplify

\frac{( - 9 + 12 i )}{( 1 + 2 i )}

3 + 6 i

Solution steps

\frac{- 9 + 12 i}{1 + 2 i}

Multiply by the conjugate

\frac{1 - 2 i}{1 - 2 i}

= \frac{( - 9 + 12 i ) ( 1 - 2 i )}{( 1 + 2 i ) ( 1 - 2 i )}

Simplify

\frac{( - 9 + 12 i ) ( 1 - 2 i )}{( 1 + 2 i ) ( 1 - 2 i )} : \frac{15 + 30 i}{5}

= \frac{15 + 30 i}{5}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{15}{5} + \frac{30}{5} i

Simplify

\frac{15}{5} + \frac{30}{5} i : 3 + 6 i

= 3 + 6 i

3 xx \leq 1 and x < - 4

π \cdot π

x^{3} + 1 < 0

4 9^{\frac{1}{2}}

(\frac{a ^{2} b ^{- 4}}{9})^{- \frac{1}{2}}