What are the solutions to the equation (n-9)(n-10)=90 ?

The solutions to the equation (n-9)(n-10)=90 are n=19,n=0

Find the zeros of (n-9)(n-10)=90

The zeros of (n-9)(n-10)=90 are n=19,n=0

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(n - 9) (n - 10) = 90

n = 19, n = 0

Solution steps

(n - 9) (n - 10) = 90

Expand

(n - 9) (n - 10) : n^{2} - 19 n + 90

n^{2} - 19 n + 90 = 90

Move

90

to the left side

n^{2} - 19 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 19)^{2} - 4 \cdot 1 \cdot 0 = 19

n_{1, 2} = \frac{- ( - 19 ) \pm 19}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 19 ) + 19}{2 \cdot 1}, n_{2} = \frac{- ( - 19 ) - 19}{2 \cdot 1}

n = \frac{- ( - 19 ) + 19}{2 \cdot 1} : 19

n = \frac{- ( - 19 ) - 19}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

n = 19, n = 0

2 + \frac{5}{9} x > x - 2

∣ 3 x ∣ > 24

- \frac{1}{2} (- 5)

445

10 0^{4}

What are the solutions to the equation (n-9)(n-10)=90 ?
The solutions to the equation (n-9)(n-10)=90 are n=19,n=0
Find the zeros of (n-9)(n-10)=90
The zeros of (n-9)(n-10)=90 are n=19,n=0