What is the answer to n(3nx+m)-m(1-3mx)=n^2+m(n+m-1) ?

The answer to n(3nx+m)-m(1-3mx)=n^2+m(n+m-1) is x= 1/3 ;\quad n\ne im,n\ne-im

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n(3nx+m)-m(1-3mx)=n^2+m(n+m-1)

n (3 n x + m) - m (1 - 3 m x) = n^{2} + m (n + m - 1)

x = \frac{1}{3}; n \neq = im, n \neq = - im

Decimal Notation

x = 0.33333 \dots

Solution steps

n (3 n x + m) - m (1 - 3 m x) = n^{2} + m (n + m - 1)

Expand

n (3 n x + m) : 3 n^{2} x + nm

3 n^{2} x + nm - m (1 - 3 m x) = n^{2} + m (n + m - 1)

Expand

- m (1 - 3 m x) : - m + 3 m^{2} x

3 n^{2} x + nm - m + 3 m^{2} x = n^{2} + m (n + m - 1)

Expand

m (n + m - 1) : nm + m^{2} - m

3 n^{2} x + nm - m + 3 m^{2} x = n^{2} + nm + m^{2} - m

Move

nm

to the right side

3 n^{2} x - m + 3 m^{2} x = m^{2} - m + n^{2}

Move

m

to the right side

3 n^{2} x + 3 m^{2} x = m^{2} + n^{2}

Factor

3 n^{2} x + 3 m^{2} x : 3 x (n^{2} + m^{2})

3 x (n^{2} + m^{2}) = m^{2} + n^{2}

Divide both sides by

3 (n^{2} + m^{2}); n \neq = im, n \neq = - im

x = \frac{1}{3}; n \neq = im, n \neq = - im

\frac{1}{2} x + \frac{1}{4} - \frac{1}{10} x = \frac{1}{5}

y = 0 + 2

x, x (n) - 3 y (n - 1) - 2 y (n - 2) = 0

12 (y + 1) = 4 (4 y - 3)

\frac{a}{5} = \frac{6}{15}

What is the answer to n(3nx+m)-m(1-3mx)=n^2+m(n+m-1) ?
The answer to n(3nx+m)-m(1-3mx)=n^2+m(n+m-1) is x= 1/3 ;\quad n\ne im,n\ne-im