What is the answer to (3x-1)(3x+3)=(3x+2)(3x-2) ?

The answer to (3x-1)(3x+3)=(3x+2)(3x-2) is x=-1/6

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(3x-1)(3x+3)=(3x+2)(3x-2)

(3 x - 1) (3 x + 3) = (3 x + 2) (3 x - 2)

x = - \frac{1}{6}

Decimal Notation

x = - 0.16666 \dots

Solution steps

(3 x - 1) (3 x + 3) = (3 x + 2) (3 x - 2)

Expand

(3 x - 1) (3 x + 3) : 9 x^{2} + 6 x - 3

Expand

(3 x + 2) (3 x - 2) : 9 x^{2} - 4

9 x^{2} + 6 x - 3 = 9 x^{2} - 4

Move

3

to the right side

9 x^{2} + 6 x = 9 x^{2} - 1

Move

9 x^{2}

to the left side

6 x = - 1

Divide both sides by

6

x = - \frac{1}{6}

7 x - 2.7 = - 6 x - 7.9

x, 6 y - x y^{2} = 1

\frac{x}{7} - 4 = 4

8 D - 16 = - 3 (- 4 D + 4)

a, a (5)^{3} - 17 (5)^{2} + b (5) + 15 = 0

What is the answer to (3x-1)(3x+3)=(3x+2)(3x-2) ?
The answer to (3x-1)(3x+3)=(3x+2)(3x-2) is x=-1/6
Solve for x: (3x-1)(3x+3)=(3x+2)(3x-2)
The solution is x=-1/6